How do you solve $3x + 3y = –6$ and $–x + y = 0$ ?

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Answer 1 · 2015-08-04T05:37:20

The solution for the system of equations is:
$color(blue)(x=-1,y=-1$

$3x+3y=–6$ .....equation $(1)$

$–x+y=0$
$x=color(blue)(y$ ........equation $(2)$

Solving through substitution:

Substituting equation $2$ in equation $1$
$3x+3y=–6$

$3 * color(blue)(y)+3y=–6$

$6y=–6$

$color(blue)(y=–1$

From equation $2$ we know that : $x=y$
So , $color(blue)(x=-1$

How do you solve 3x + 3y = –63x + 3y = –6 and –x + y = 0–x + y = 0?