Question

How do you solve `3x^(4/3) + 5 = 53` and find any extraneous solutions?

Answer 1

`x=8`

Explanation:

`3x^(4/3)+5=53`
or
`3x^(4/3)=53-5`
or
`3x^(4/3)=48`
or
`x^(4/3)=48/3`
or
`x^(4/3)=16`
or
`x=16^(3/4)`
or
`x=root4(16^3)`
or
`x=(root4(2times2times2times2))^3`
or
`x=2^3`
or
`x=8`