How do you solve #-3x-6=5#?

2 Answers
Dec 30, 2016

#x=-11/3#. See below.

Explanation:

To isolate #x#, we can begin by adding #6# to both sides. We see that it is subtracted on the left side, so we can "undo" this by adding it. It is important that, whatever we do to one side of the equation, we must also do to the other.

#=>-3xcancel(-6+6)=5+6#

#=>-3x=11#

Now we see that we are multiplying #x# by #-3# on the left, which we can undo with division. We divide both sides of the equation by #-3#.

#=>(cancel(-3)x)/cancel(-3)=11/-3#

This leaves us with #x=-11/3#.

Hope this helps!

Dec 30, 2016

#x=-11/3#

Explanation:

Leave - 3x on the left side of the equation and collect numeric values on the right side.

add 6 to both sides.

#-3xcancel(-6)cancel(+6)=5+6#

#rArr-3x=11#

To solve for x, divide both sides by - 3

#(cancel(-3) x)/cancel(-3)=11/(-3)#

#rArrx=-11/3" is the solution"#