How do you solve $3x-7y=-13$ and $-2x+3y=7$ ?

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Answer 1 · 2015-08-03T08:26:57

The solutions for the system of equations are
$color(blue)(x=-2,y=1$

$3x−7y=−13$ , Multiplying this equation with $2$
$color(blue)(6x)−14y=-26$ ......equation $(1)$

$−2x+3y=7$ , Multiplying this equation with $3$
$−color(blue)(6x)+9y=21$ .......equation $(2)$

Solving through elimination

Adding the two equations results in elimination of $color(blue)(6x$
$cancel(6x)−14y=-26$

$cancel(−6x)+9y=21$

$-5y=-5$
$color(blue)(y=1$

Now, we find $x$ by substituting $y$ in equation $(1)$
$3x−7y=−13$

$3x−7*1=−13$

$3x=−13+7$

$x=-6/3$

$color(blue)(x=-2$

How do you solve 3x-7y=-133x-7y=-13 and -2x+3y=7-2x+3y=7?