How do you solve $3 x + y = - 11$ $3x + y = -11$ and $2 x - (\frac{2}{3}) y = - \frac{2}{3}$ $2x - (2/3)y = -2/3$ ?

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How do you solve $3 x + y = - 11$ $3x + y = -11$ and $2 x - (\frac{2}{3}) y = - \frac{2}{3}$ $2x - (2/3)y = -2/3$ ?

1 Answer

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Answer 1 · 2018-06-05T06:38:19

$x = - 2, y = - 5$ $x=-2,y=-5$

Explanation:

Multiply the second equation by 3

$6 x - 2 y = - 2$ $6x-2y=-2$

Multiply the first equation by 2

$6 x + 2 y = - 22$ $6x+2y=-22$

We have two new equations with the same number of $y$ $y$ s but with different signs. By adding these two equations we can remove the $y$ $y$ s and solve for $x$ $x$ .

$12 x = - 24$ $12x=-24$

$x = - 2$ $x=-2$

Put $x = - 2$ $x=-2$ into the first equation

$\Rightarrow 3 \times - 2 + y = - 11$ $=> 3xx-2+y=-11$

$- 6 + y = - 11$ $-6+y=-11$

$y = - 5$ $y=-5$

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How do you solve $3 x + y = - 11$ $3x + y = -11$ and $2 x - (\frac{2}{3}) y = - \frac{2}{3}$ $2x - (2/3)y = -2/3$ ?

1 Answer

Explanation:

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How do you solve 3x+y=−113x + y = -11 and 2x−(23)y=−232x - (2/3)y = -2/3?

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Explanation:

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How do you solve $3 x + y = - 11$ $3x + y = -11$ and $2 x - (\frac{2}{3}) y = - \frac{2}{3}$ $2x - (2/3)y = -2/3$ ?