How do you solve 3x+y=3 and 2x+3y=-5?

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Answer 1 · 2015-09-05T07:34:11

The solution is
$x = 2, y = - 3$ $color(blue)(x=2,y=-3$

$3 x + y = 3$ $3x+y=3$ , multiplying the equation by $3$ $3$
$9 x + 3 y = 9$ $9x+color(blue)(3y)=9$ ........equation $1$ $1$

$2 x + 3 y = - 5$ $2x+color(blue)(3y)=-5$ ....equation $2$ $2$

Solving by elimination as subtracting the two equations eliminates $3 y$ $color(blue)(3y$

Subtracting equation $2$ $2$ from $1$ $1$
$9x+cancelcolor(blue)(3y)=9$

$- 2x-cancelcolor(blue)(3y)=+5$

$7x=14$
$color(blue)(x=2$

Finding $y$ by substituting $x$ in equation $1$
$3x+y=3$
$y=3-3x$
$y=3-3*2$
$y=3-6$
$color(blue)(y=-3$