How do you solve $3 x - y = 3$ $3x-y=3$ and $- 2 x + y = 2$ $-2x+y=2$ ?

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Answer 1 · 2015-08-02T23:12:28

$x = 5, y = 12$ $color(red)( x=5,y=12)$

One way is to use the method of elimination.

Step 1. Enter the equations.

[1] $3 x - y = 3$ $3x-y=3$
[2] $- 2 x + y = 2$ $-2x+y=2$

Step 2. Add the equations.

[3] $x = 5$ $x=5$

Step 3. Substitute Equation 3 in Equation 2.

$- 2 x + y = 2$ $-2x+y=2$

$- 2 (5) + y = 2$ $-2(5)+y=2$

$- 10 + y = 2$ $-10+y =2$

$y = 12$ $y=12$

Solution: $x = 5, y = 12$ $x=5,y=12$

Check: Substitute the values of $x$ $x$ and $y$ $y$ in Equation 1.

$3 x - y = 3$ $3x-y=3$
$3 (5) - 12 = 3$ $3(5)-12=3$
$15 - 12 = 3$ $15-12=3$
$3 = 3$ $3=3$

How do you solve 3x-y=33x−y=33x-y=3 and -2x+y=2−2x+y=2-2x+y=2?