How do you solve $3 x - y = - 4$ $3x-y= -4$ and $3 x - y = 0$ $3x-y=0$ ?

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Answer 1 · 2015-08-05T20:43:04

There is no solution.

We can try the method of elimination.

Your equations are

[1] $3 x - y = 4$ $3x-y=4$
[2] $3 x - y = 0$ $3x-y=0$

Subtract Equation 2 from Equation 1.

$0 = 4$ $0=4$

This is impossible, so there is no solution.

We can see why there is no solution if we plot the two graphs:

[1] $y = 3 x - 4$ $y=3x-4$
[2] $y = 3 x$ $y=3x$

Graph

The graphs are parallel and do not intersect. Hence there can be no solution.

How do you solve 3x−y=−43x-y= -4 and 3x−y=03x-y=0?