How do you solve $4 \sqrt{3 m^{2} - 15} = 14 ?$ $4 sqrt(3m^2-15)=14?$ ?

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Answer 1 · 2015-07-20T14:54:38

$m \approx 3.01$ $color(blue)(m approx 3.01$

$4 \sqrt{3 m^{2} - 15} = 14$ $4sqrt(3m^2−15)=14$

Squaring both sides:
${(4 \sqrt{3 m^{2} - 15})}^{2} = 14^{2}$ $(4sqrt(3m^2−15))^2=14^2$

$16 \cdot (3 m^{2} - 15) = 196$ $16 * (3m^2-15) =196$

$48 m^{2} - 240 = 196$ $48m^2 - 240 = 196$

$48 m^{2} = 436$ $48m^2 = 436$

$m^{2} = \frac{436}{48}$ $m^2 = 436/48$
$m^{2} = 9.08$ $m^2 = 9.08$

$m \approx 3.01$ $color(blue)(m approx 3.01$

How do you solve 4√3m2−15=14?4 sqrt(3m^2-15)=14??