How do you solve $4/(sqrt(r+4))=2$ ?

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Answer 1 · 2015-07-20T15:14:18

$color(green)(r=0$

$4/(sqrt(r+4))=2$

$4=2 ( sqrt(r+4))$

Squaring both sides:
$4^2=(2 ( sqrt(r+4))^2$

$16=4 *(r+4)$
$16=4r+16$

$4r=0$

$color(green)(r=0$

How do you solve 4/(sqrt(r+4))=24/(sqrt(r+4))=2?