Question

How do you solve `4/v + 1/5 = 1` and find any extraneous solutions?

Answer 1

`v=5`

Explanation:

`"subtract " 1/5" from both sides"`

`4/vcancel(+1/5)cancel(-1/5)=1-1/5`

`rArr4/v=4/5`

`"since the fractions are equal and have the same numerator"`

`rArrv=5`

`color(blue)"As a check"`

`"left side "=4/5+1/5=5/5=1=" right side"`

`rArrv=5" is the solution"`