How do you solve $4 \sqrt{7 + 3 z} = 2$ $4sqrt(7 + 3z) = 2$ ?

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Answer 1 · 2015-08-19T12:47:00

$z = - \frac{9}{4}$ $color(blue)(z=-9/4$

$4 \sqrt{7 + 3 z} = 2$ $4sqrt(7+3z)=2$

Squaring the L.H.S and R.H.S:

${(4 \sqrt{7 + 3 z})}^{2} = 2^{2}$ $(4sqrt(7+3z))^2=2^2$

$16 (7 + 3 z) = 4$ $16(7+3z)=4$

$7 + 3 z = \frac{4}{16}$ $7+3z=4/16$

$7 + 3 z = \frac{1}{4}$ $7+3z=1/4$

$7 \cdot 4 + 3 z \cdot 4 = \frac{1}{4} \cdot 4$ $7*4+3z*4=1/4*4$

$28 + 12 z = 1$ $28+12z=1$

$12 z = 1 - 28$ $12z=1-28$

$z = - \frac{27}{12}$ $z=-27/12$

$z = - \frac{9}{4}$ $color(blue)(z=-9/4$

How do you solve 4sqrt(7 + 3z) = 24√7+3z=24sqrt(7 + 3z) = 2?