How do you solve $4sqrt(x)=-x-3$ ?

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Answer 1 · 2018-05-07T02:02:22

No real solution exists

No real solution exists as L H S is always positive and R H S always negative for any positive value of x.

When x is negative, L H S becomes imaginary.

How do you solve 4sqrt(x)=-x-3 4sqrt(x)=-x-3 ?