How do you solve $4 x^{2} + 5 x - 6 = 0$ $4x^2+5x-6=0$ using the quadratic formula?

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Answer 1 · 2016-12-05T23:14:46

$x = \frac{3}{4}$ $x = 3/4$ and $x = - 2$ $x = -2$

Playing with different factors of $4$ $4$ and $6$ $6$ you factor the quadratic to:

$(4 x - 3) (x + 2) = 0$ $(4x - 3)(x + 2) = 0$

Now solve each term for $0$ $0$ :

4x - 3 = 0#

$4 x - 3 + 3 = 0 + 3$ $4x - 3 + 3 = 0 + 3$

$4 x = 3$ $4x = 3$

$\frac{4 x}{4} = \frac{3}{4}$ $(4x)/4 = 3/4$

$x = \frac{3}{4}$ $x = 3/4$

and

$x + 2 = 0$ $x + 2 = 0$

$x + 2 - 2 = 0 - 2$ $x + 2 - 2 = 0 - 2$

$x = - 2$ $x = -2$

How do you solve 4x^2+5x-6=04x2+5x−6=04x^2+5x-6=0 using the quadratic formula?