How do you solve $4x-3y=14$ and $y=-3x+4$ ?

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Answer 1 · 2015-08-04T05:33:58

The solution for the system of equations is
$color(blue)(x=2,y=-2$

$4x−3y=14$ .....equation $(1)$
$y=color(blue)(−3x+4$ .....equation $(2)$

Solving by substitution

Substituting equation $2$ in equation $1$

$4x−3 * (color(blue)(−3x+4))=14$

$4x +9x -12=14$

$13x =14 +12$

$13x =26$

$color(blue)(x=2$

Finding $y$ by substituting $x$ in equation $1$

$4x−3y=14$

$4 * 2−3y=14$

$8−3y=14$

$8-14 =3y$

$3y = -6$

$color(blue)(y=-2$

How do you solve 4x-3y=144x-3y=14 and y=-3x+4y=-3x+4?