How do you solve $4 x + 3 y = - 7$ $4x+3y=-7$ and $5 x - 2 y = - 26$ $5x-2y=-26$ ?

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Answer 1 · 2016-05-06T21:54:47

Combine the equations to eliminate $y$ $y$ and solve for $x$ $x$ . Then substitute the value found for $x$ $x$ and solve for $y$ $y$ to find:

${ (x = -4), (y = 3) :}$

Multiply the first equation by $2$ and the second by $3$ to get:

${ (8x+6y = -14), (15x-6y=-78) :}$

Add these two equations together to get:

$23x = -92$

Divide both sides by $23$ to get:

$x = -4$

Substitute this value of $x$ in the first given equation to get:

$-7 = 4(-4)+3y = -16+3y$

Add $16$ to both ends and transpose to get:

$3y = 9$

Divide both sides by $3$ to get:

$y = 3$

How do you solve 4x+3y=-74x+3y=−74x+3y=-7 and 5x-2y=-265x−2y=−265x-2y=-26?