How do you solve 4x - y = -5 and -2x + 3y = 10?

1 Answer
Sep 6, 2015

{(x=-1/2), (y=3):}

Explanation:

Your system of equations looks like this

{(4x-y = -5), (-2x + 3y = 10):}

Multiply the second equation by 2 to get

{(4x-y = -5), (-4x + 6y = 20):}

Notice that if you add the left-hand side of the equations and the right-hand sides of the equations separately, you can eliminate the x-term.

This will allow you to find the value of y, since you'll be left with one equation with one unknown, y.

{(4x-y = -5), (-4x + 6y = 20):}
stackrel("--------------------------------------------")
color(red)(cancel(color(black)(4x))) - y - color(red)(cancel(color(black)(4x))) + 6y = -5 + 20

5y = 15 implies y = color(green)(3)

Now take the value of y into one of the two original equations to solve for x

4x - 3 = -5

4x = -2 implies x = color(green)(-1/2)