How do you solve $5=sqrt(1- 8x)$ and find any extraneous solutions?

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Answer 1 · 2016-07-07T17:53:00

$x = -3$

Square both sides

$5^2 = (sqrt(1-8x))^2$

$25 = 1-8x$

Isolate the variable

$24 = -8x$

$-3 = x$

How do you solve 5=sqrt(1- 8x)5=sqrt(1- 8x) and find any extraneous solutions?