How do you solve $5(x + 4) = 10$ ?

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Answer 1 · 2016-04-05T13:08:29

$x=-2$

$color(blue)(5(x+4)=10$

Use distributive property

$color(brown)(a(b+c)=ab+ac$

$rarr5x+20=10$

Subtract both sides by $20$

$rarr5x+20-20=10-20$

$rarr5x=-10$

Divide both sides by $5$

$rarr(cancel5^1x)/cancel5^1=-10/5$

$color(green)(rArrx=-2$

Check

$5(-2+4)=10$

$5(2)=10$

$10=10$

Correct!

How do you solve 5(x + 4) = 105(x + 4) = 10?