Question

How do you solve `5/y-2=y+2`?

Answer 1

`y= -1 " or " y=-5`

Explanation:

`5/y-2 = y+2" "larr` move the -2 to the RHS

`5/y = y+4" "larrxxy` to get rid of the fractions.

`5 = y^2 + 4y" "larr` make = 0.

`y^2 +4y -5 =0`

`(y-1)(y+5)=0" "larr` solve for y.

`y-1 =0 rarr y=1`

`y+5=0rarr y=-5`