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How do you solve $\frac{5}{y - 3} - \frac{30}{y^{2} - 9} = 1$ $5/(y-3) - 30/(y^2-9)= 1$ ?

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May 15, 2015

$[\frac{5 (y + 3)}{y^{2} - 9}] - \frac{30}{y^{2} - 9} = 1$ $[(5(y + 3))/(y^2 - 9) ] - 30/(y^2 - 9) = 1$

5y + 15 - 30 = (y - 3)(y + 3)

5(y - 3) = (y - 3)(y + 3) -> 5 = y + 3 -> y = 2.

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