How do you solve $(5/(y+5)) = (4/(y-3))$ ?

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Answer 1 · 2016-02-13T05:35:35

$color(green)(y=35$

$(5/(y+5))=(4/(y-3))$

Remove the brackets:

$rarr5/(y+5)=4/(y-3)$

Cross multiply $color(blue)(a/b=c/d,ad=bc$

$rarr5(y-3)=4(y+5)$

Use distributive property $color(orange)(a(b+c)=ab+ac$

$rarr5y-15=4y+20$

Subtract $4y$ both sides:

$rarry-15=20$

Add $15$ both sides:

$rArrcolor(green)(y=35$

How do you solve (5/(y+5)) = (4/(y-3)) (5/(y+5)) = (4/(y-3)) ?