How do you solve $5x^2+2x-3=0$ using the quadratic formula?

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Answer 1 · 2016-03-06T14:56:40

The solutions are:
$x = color(green)(3/5$

$x =color(green)(- 1$

$5x^2 +2x -3=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=5, b=2, c=-3$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (2)^2-(4*5* (-3))$

$= 4 +60 = 64$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-2)+-sqrt(64))/(2*5) = (-2+-8)/10$

$x= (-2+8)/10= 6/10 = color(green)(3/5$

$x= (-2-8)/10= -10/10 =color(green)(- 1$

How do you solve 5x^2+2x-3=05x^2+2x-3=0 using the quadratic formula?