How do you solve $5x^2-8x=6$ using the quadratic formula?

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Answer 1 · 2018-06-11T02:36:23

$x=(4+-sqrt46)/5$

$5x^2-8x=6$
$5x^2-8x-6=0$

Remember the general form of an equation is $ax^2+bx+c=0$ where a,b and c are constants.
Using the quadratic formula.
$x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(8+-sqrt(64+120))/(2times5)$

$x=(8+-sqrt184)/10$

$x=(8+-2sqrt46)/10$

$x=(4+-sqrt46)/5$

How do you solve 5x^2-8x=65x^2-8x=6 using the quadratic formula?