How do you solve $5 x + 4 y = 2$ $5x + 4y = 2$ and $3 x - 4 y = 14$ $3x - 4y = 14$ ?

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Answer 1 · 2015-08-02T14:00:06

The solution for the system of equations is
$x = 2, y = - 2$ $color(blue)(x=2,y=-2$

Upon adding the two equations we can **eliminate ** $4 y$ $color(blue)(4y)$

$5x+color(blue)(cancel4y)=2$ .....equation $(1)$
$3x−color(blue)(cancel4y)=14$ .....equation $(2)$

$8x=16$
$color(blue)(x=2$

Substituting the value of $x$ in the first equation to find $y$
$5x+4y=2$

$5 * (2)+4y=2$

$10 +4y=2$

$4y=-8$
$color(blue)(y=-2$

How do you solve 5x + 4y = 25x+4y=25x + 4y = 2 and 3x - 4y = 143x−4y=143x - 4y = 14?