How do you solve $5x+7=27$ ?

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Answer 1 · 2016-02-03T15:24:31

$5x+7=27$

$rarr5x=27-7$

$rarr5x=20$

$rarrx=20/5=4$

Answer 2 · 2016-02-03T15:25:02

Subtract $7$ from both sides of the equation
then divide both sides by $5$ to isolate $x$
giving $x=4$

If
$color(white)("XXX")5x+7 = 27$
then
$color(white)("XXX")5x+7color(red)(-7)=27color(red)(-7)$
which simplifies as
$color(white)("XXX")5x=20$

If
$color(white)("XXX")5x=20$
then
$color(white)("XXX")(5x)color(red)(div5) = 20color(red)(div5)$
which simplifies as
$color(white)("XXX")x=4$

How do you solve 5x+7=275x+7=27?