How do you solve $5 x + 7 = \frac{3}{2} x + 63$ $5x + 7= \frac { 3} { 2} x + 63$ ?

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Answer 1 · 2017-03-04T18:39:22

$x = 16$ $x=16$

$5 x + 7 = \frac{3}{2} x + 63$ $5x+7=3/2x+63$

$:.10/2x-3/2x=63-7$

$:.7/2x=56$

multiply L.HS. and R.H.S. by $color(blue) 2$

$:.color(blue)cancel2 xx 7/cancel2x=56 xx color(blue)2$

$:.7x=112$

$:.color(blue)(x=16$

check:

substitute $x=color(blue)16$

$color(blue)5(color(blue)16)+7=3/2(color(blue)16)+63$

$:.80+7=48/2+63$

$:.87=24+63$

$:.87=87$

How do you solve 5x + 7= \frac { 3} { 2} x + 635x+7=32x+635x + 7= \frac { 3} { 2} x + 63?