How do you solve $-6+10(5-2x)=1$ ?

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Answer 1 · 2018-03-27T00:14:29

$x=43/20$

$-6+10(5-2x)=1$

$-6+50-20x=1$

$44-20x=1$

Then subtract the $44$ from both sides, and then divide both sides by $-20$ .

$-20x = -43$

$x = (-43)/(-20)$

How do you solve -6+10(5-2x)=1-6+10(5-2x)=1?