How do you solve $6 + 2 x = 38$ $6+ 2x = 38$ ?

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Answer 1 · 2018-03-28T18:21:00

$x = 16$ $x=16$

$6 + 2 x = 38$ $6+2x=38$ (Subtract 6 from both sides)

$2 x = 32$ $2x=32$ (Divide both sides by 2 to isolate the variable)

$x = 16$ $x=16$

Check the answer by plugging in the answer into the initial equation:

$6 + 2 (16) = 38$ $6+ 2(16) =38$

$6 + 32 = 38$ $6+32=38$

$38 = 38$ $38=38$

Answer 2 · 2018-03-28T18:25:14

$x = 16$ $x=16$

So first you have to subtract $6$ $6$ from both sides. When you subtract from $38$ $38$ , you get $32$ $32$ . Now you just have

$2 x = 32$ $2x=32$

left. This is when you use division to get $x$ $x$ by itself. Now you divide by $2$ $2$ on both sides

$\frac{2 x}{2} = \frac{32}{2}$ $(2x)/2 = 32/2$

and you do that to get $x$ $x$ alone. So now it's just

$x = 16$ $x=16$

because $\frac{32}{2}$ $32/2$ is $6$ $6$ .

How do you solve 6+ 2x = 386+2x=386+ 2x = 38?