How do you solve 63= - 1+ k ^ { \frac { 3} { 2} }?

1 Answer
Feb 21, 2017

Change k^(3/2) to k

k =16

Explanation:

k^(3/2) can be written as root2( k)^3

63 = -1+k^(3/2)

Add 1 to both sides;

63+1= k^(3/2)

64=k^(3/2)

To remove the cube take the cube root of 64, which is 4.

root3 64 = root3 (k^(3/2)

4 = k^(1/2)

And then to remove the power of 1/2 from k you take

4^2 and (k^(1/2))^2

Which gives you the answer:

16=k