How do you solve $(6b)^(1/2)=(8-2b)^(1/2)$ ?

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Answer 1 · 2017-04-07T06:09:50

First get rid of square root, then you will get $b=1$

Your equation is (after getting rid of the square root:
$6b=8-2b$
From there,
$6b+2b=8$
$b=1$

How do you solve (6b)^(1/2)=(8-2b)^(1/2)(6b)^(1/2)=(8-2b)^(1/2)?