How do you solve $(6g - 5)^(1/3) + 2 = -3$ ?

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Answer 1 · 2018-05-19T16:51:55

$g = -20$

$(6g-5)^(1/3) + 2 = -3$

Is the same thing as:

$root(3)(6g-5) + 2 = -3$

$root(3)(6g-5) = -5$

Cube both sides of the equation:

$(root(3)(6g-5))^3 = (-5)^3$

$6g-5 = -125$

$6g = -120$

$g = -20$

How do you solve (6g - 5)^(1/3) + 2 = -3 (6g - 5)^(1/3) + 2 = -3 ?