How do you solve $6r - 33r- 55= 53$ ?

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Answer 1 · 2017-12-07T09:11:15

$r=-4$

First, we will add the $r$ terms together.

$6r-33r=-27r$

$-27r-55=53$

Now we get like terms on each side, so we add $55$ to each side.

$-27r-55+55=-27r=108$

$-27r=108$

Now we just divide by $-27$ to get $r$ on its own.

$r=108/-27=-4$

$r=-4$

How do you solve 6r - 33r- 55= 536r - 33r- 55= 53?