How do you solve #6w+11=6#?

1 Answer
May 2, 2018

#w = -5/6#

Explanation:

To solve this, we want to get our variable #w# alone. The first thing we do is subtract #color(blue)(11)# from both sides of the equation:
#6w + 11 quadcolor(blue)(-quad11) = 6 quadcolor(blue)(-quad11)#

#6w = -5#

Divide both sides by #color(blue)6#:
#(6w)/color(blue)6 = (-5)/color(blue)6#

So the answer is
#w = -5/6#

Hope this helps!