How do you solve 6x+y=30 and 7x+2y=32?

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How do you solve 6x+y=30 and 7x+2y=32?

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Answer 1 · 2016-08-14T13:27:59

$x = 5.6$ $x=5.6$
$y = - 3.6$ $y=-3.6$

Explanation:

Multiplying both the sides of the equation $6 x + y = 30$ $6x+y=30$ by $2$ $2$
We get
$12 x + 2 y = 60$ $12x+2y=60$
$7 x + 2 y = 32$ $7x+2y=32$
Subtracting $7 x + 2 y = 32$ $7x+2y=32$ from $12 x + 2 y = 60$ $12x+2y=60$
we get
$12 x - 7 x + 2 y - 2 y = 60 - 32$ $12x-7x+2y-2y=60-32$
or
$5 x + 0 = 28$ $5x+0=28$
or
$5 x = 28$ $5x=28$
or
$x = \frac{28}{5}$ $x=28/5$
or
$x = 5.6$ $x=5.6$ --------------------------Ans $1$ $1$

By plugging the value $x = 5.6$ $x=5.6$ in the equation $6 x + y = 30$ $6x+y=30$
We get

$6 \times 5.6 + y = 30$ $6times5.6+y=30$
or
$33.6 + y = 30$ $33.6+y=30$
or
$y = 30 - 33.6$ $y=30-33.6$
or
$y = - 3.6$ $y=-3.6$ ------------------------------Ans $2$ $2$

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How do you solve 6x+y=30 and 7x+2y=32?

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