Question

How do you solve 6y + 4x = 12 and -6x + y = -8?

Answer 1

I found:
`x=3/2`
`y=1`

Explanation:

You can rearrange the two equations and write:
`{(4x+6y=12),(-6x+y=-8):}`
we can now multiply the second equation by `-6` to get:
`{(4x+6y=12),(color(red)(36x-6y=48)):}`
we now add together (by column) the two equations:
`40x+0=60` so that:
`x=60/40=6/4=3/2`
substitute this value into the first equation:
`4(3/2)+6y=12`
`6+6y=12`
`y=1`

hope it helps!