How do you solve $7 + \sqrt{2 x - 1} = 10$ $7 + sqrt[2x - 1] = 10$ ?

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Answer 1 · 2015-08-05T18:07:30

$x = 5$ $x = 5$

First, start by isolating the readical on one side of the equation. This can be done by adding $- 7$ $-7$ to both sides

$color(red)(cancel(color(black)(7))) - color(red)(cancel(color(black)(7))) + sqrt(2x-1) = 10 - 7$

$sqrt(2x-1) = 3$

To get rid of the radical term, square both sides of the equation

$(sqrt(2x-1))^2 = 3^2$

$2x-1 = 9$

$2x = 10 => x = 10/2 = color(green)(5)$

How do you solve 7 + sqrt[2x - 1] = 107+√2x−1=107 + sqrt[2x - 1] = 10?