How do you solve $7 x + 9 = \frac{15}{2} x + 6$ $7x + 9 = 15/2x + 6$ ?

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How do you solve $7 x + 9 = \frac{15}{2} x + 6$ $7x + 9 = 15/2x + 6$ ?

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Answer 1 · 2016-03-04T01:30:51

$x = 6$ $x = 6$

Explanation:

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$7 x + 9 = \frac{15}{2} x + 6$ $7x+9=15/2x+6$ Begin by multiplying by 2 to eliminate the fraction.
$2 [7 x + 9 = \frac{15}{2} x + 6]$ $2[7x+9=15/2x+6]$ = $14 x + 18 = 15 x + 12$ $14x+18=15x+12$
Move the variables to the same side by additive inverse
$14 x + 18 - 14 x = 15 x + 12 - 14 x$ $14x+18-14x =15x+12 -14x$
$18 = 1 x + 12$ $18=1x+12$ isolate the variable term by additive inverse
$18 - 12 = 1 x + 12 - 12$ $18 -12=1x+12 -12$
$6 = x$ $6 = x$

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How do you solve $7 x + 9 = \frac{15}{2} x + 6$ $7x + 9 = 15/2x + 6$ ?

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