How do you solve $8 = 10 (\sqrt{x}) + 3$ $8=10 (sqrt x) + 3$ ?

Question

1284 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-08T19:05:17

In an equation like this, you first put the $x$ $x$ 's to one side and the numbers to the other.

Subtract 3 from both sides:
$\to 5 = 10 \sqrt{x}$ $->5=10sqrtx$

Then you divide both sides by 10 to isolate the $\sqrt{x}$ $sqrtx$
$\to \frac{1}{2} = \sqrt{x} \to \sqrt{x} = \frac{1}{2}$ $->1/2=sqrtx->sqrtx=1/2$

As a final step, you can square both sides:
$\to {(\sqrt{x})}^{2} = {(\frac{1}{2})}^{2} \to x = \frac{1}{4}$ $->(sqrtx)^2=(1/2)^2->x=1/4$

How do you solve 8=10 (sqrt x) + 38=10(√x)+38=10 (sqrt x) + 3?