How do you solve $8(3a-b) + 4(2b-a)$ ?

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Answer 1 · 2018-06-18T15:13:36

See a solution process below:

To simplify this expression, first eliminate the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$color(red)(8)(3a - b) + color(blue)(4)(2b - a) =>$

$(color(red)(8) xx 3a) - (color(red)(8) xx b) + (color(blue)(4) xx 2b) - (color(blue)(4) xx a) =>$

$24a - 8b + 8b - 4a$

Next, group like terms:

$24a - 4a - 8b + 8b$

Now, combine like terms:

$(24 - 4)a + (-8 + 8)b =>$

$20a + 0b =>$

$20a$

How do you solve 8(3a-b) + 4(2b-a)8(3a-b) + 4(2b-a)?