How do you solve $[9/(x-5)] – 1 = [8/(x+5)]$ ?

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Answer 1 · 2016-08-04T10:15:06

The Soln. $x=11, or, x=-10$

$9/(x-5)-1=8/(x+5)$

$rArr 9/(x-5)-8/(x+5)=1$ .

$rArr (9(x+5)-8(x-5))/{(x-5)(x+5)}=1$

$rArr (x+85)/(x^2-25)=1$

$rArrx+85=x^2-25$

$rArr x^2-x-110=0$

$rArr (x-11)(x+10)=0$

Hence, the Soln. $x=11, or, x=-10$

How do you solve [9/(x-5)] – 1 = [8/(x+5)][9/(x-5)] – 1 = [8/(x+5)]?