How do you solve (9/x)+9/(x-2) = 12?

1 Answer
Dec 5, 2016

x = 1/2 and x = 3

Explanation:

First, you can get each fraction over a common denominator, in this case x(x - 2), so the fractions can be added:

((x-2)/(x-2))(9/x) + (x/x)(9/(x-2)) = 12

(9(x-2) + 9x)/(x(x-2)) = 12

We can now expand and add the numerator:

(9x-18 + 9x)/(x(x-2)) = 12

(18x-18)/(x(x-2)) = 12

We can now eliminate the fraction through multiplication on each side of the equation to keep the equation balanced:

(18x-18)/(x^2-2x) = 12

(x^2 - 2x)(18x - 18)/(x^2-2x) = 12(x^2 - 2x)

cancel((x^2 - 2x))(18x - 18)/cancel((x^2-2x)) = 12x^2 - 24x

18x - 18 = 12x^2 - 24x

We can now make a single quadratic and factor:

18x - 18 - 18x + 18 = 12x^2 - 24x - 18x + 18

12x^2 - 42x + 18 = 0

(6x - 3)(2x - 6) = 0

We can now solve each factor for 0:

6x - 3 = 0

6x - 3 + 3 = 0 + 3

6x = 3

(6x)/6 = 3/6

x = 1/2

and

2x - 6 = 0

2x - 6 + 6 = 0 + 6

2x = 6

(2x)/2 = 6/2

x = 3