Question

How do you solve `d/-4+3=15`?

Answer 1

`d=-48`

Explanation:

To eliminate the fraction on the left side along with the leading negative sign, multiply `color(blue)"all terms"` by -4.

`cancel(-4)^1xxd/cancel(-4)^1+(-4xx3)=(-4xx15)`

`rArrd-12=-60`

To solve for d, add 12 to both sides.

`d cancel(-12)cancel(+12)=-60+12`

`rArrd=-48" is the solution to the equation."`