How do you solve for t in #2/7(t+2/3)=1/5(t-2/3)#?

Question

8063 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-09-28T13:42:41

We can solve the question using the distributive property.

#2/7 ( t+ 2/3) = 1/5 (t-2/3)#

Multiplying , we get

#(2/7) * t + (2/7)*(2/3) = (1/5 ) * t - (1/5) * (2/3)#

#(2t) /7 + 4/21 = t/5 - 2/15#

Taking the like terms to one side of the equation;

#(2t)/7 -t/5 = -2/15 -4/21#

Taking LCM,

#(10t - 7t ) / 35 = ((-2 * 7 ) + (-4 * 5)) / 105#

#(3t) / 35 = -34 /105#

#3t = (-34*35 ) / 105#

#3t = (-34 * 1 ) / 3#

#3t = -34 / 3#

#t = -34 /9 = -3.7 7 or -4#