How do you solve $\frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}$ ?

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Answer 1 · 2018-04-30T20:42:44

$n = 9$

First you want to have like terms on the same side. Subtract 3 1/3 from both sides.

$2/3n = 6$

Now multiply both sides by the reciprocal of 2/3, 3/2.

$n = 9$

Check:
$(2/3 * 9) + 3 1/3 = 9 1/3$

$6 + 3 1/3 = 9 1/3$

$9 1/3 = 9 1/3$

Answer 2 · 2018-04-30T20:42:53

$n=9$

First, subtract $3 1/3$ from $9 1/3$ to get $6$ and from the left side. This should give you the equation

$2/3 n =6$

In order to solve for $n$ , we multiply both sides by the reciprocal of $2/3$ , which is $3/2$ .

$6$ multiplied by $3/2$ is

$6 * 3/2 = 18/2 = 9$

so

$2/3n * 3/2 = 9$

How do you solve \frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}\frac { 2} { 3} n + 3\frac { 1} { 3} = 9\frac { 1} { 3}?