How do you solve $\frac { k } { 6} + 8= 7$ ?

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Answer 1 · 2017-03-01T07:39:54

$k = -6$

Subtract the $8$ from both sides:

$k/6 +8 - 8 = 7 - 8$
$k/6 = -1$

Multiple both sides of the equation by $6$ :
$(6k)/6 = -1(6)$
$k = -6$

How do you solve \frac { k } { 6} + 8= 7\frac { k } { 6} + 8= 7?