How do you solve $(\frac{g + 4}{g - 2}) = (\frac{g - 5}{g - 8})$ $((g + 4) / (g - 2)) = ((g - 5) / (g - 8))$ ?

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How do you solve $(\frac{g + 4}{g - 2}) = (\frac{g - 5}{g - 8})$ $((g + 4) / (g - 2)) = ((g - 5) / (g - 8))$ ?

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Answer 1 · 2016-03-02T19:49:27

g = 14

Explanation:

Two equal fractions. Eliminate fractions by $cross multiplying$ $color(blue) " cross multiplying "$

hence: (g + 4 )(g - 8 ) = (g - 5 )(g - 2 )

distribute brackets

$\Rightarrow g^{2} - 4 g - 32 = g^{2} - 7 g + 10$ $rArr g^2 - 4g - 32 = g^2 - 7g + 10$

collect like terms , variables on left , numbers on right.

$g^{2} - g^{2} - 4 g + 7 g = 10 + 32$ $g^2 - g^2 - 4g + 7g = 10 + 32$

hence : 3g = 42 → g = 14

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How do you solve $(\frac{g + 4}{g - 2}) = (\frac{g - 5}{g - 8})$ $((g + 4) / (g - 2)) = ((g - 5) / (g - 8))$ ?

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How do you solve (g+4g−2)=(g−5g−8)((g + 4) / (g - 2)) = ((g - 5) / (g - 8))?

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Explanation:

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How do you solve $(\frac{g + 4}{g - 2}) = (\frac{g - 5}{g - 8})$ $((g + 4) / (g - 2)) = ((g - 5) / (g - 8))$ ?