How do you solve $\frac{n}{3} - 8 = - 2$ $n/3-8=-2$ ?

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Answer 1 · 2017-08-08T05:26:26

$n = 18$ $n=18$

Given -

$\frac{n}{3} - 8 = - 2$ $n/3-8=-2$

$\frac{n}{3} = - 2 + 8 = 6$ $n/3=-2+8=6$
$n = 6 \times 3 = 18$ $n=6xx 3=18$
$n = 18$ $n=18$

How do you solve n3−8=−2n/3-8=-2?