How do you solve $n/4 - 3 =4$ ?

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Answer 1 · 2018-03-26T22:46:39

The solution is $n=28$ .

First, add $3$ to both sides. Then, multiply by $4$ . Here's what that process looks like:

$n/4-3=4$

$n/4-3color(blue)+color(blue)3=4color(blue)+color(blue)3$

$n/4color(red)cancelcolor(black)(-color(black)3color(blue)+color(blue)3)=4color(blue)+color(blue)3$

$n/4=4color(blue)+color(blue)3$

$n/4=7$

$n/4color(blue)(*4)=7color(blue)(*4)$

$n/color(red)cancelcolor(black)4color(blue)(*color(red)cancelcolor(blue)4)=7color(blue)(*4)$

$n=7color(blue)(*4)$

$n=28$

This is the answer. Hope this helped!

How do you solve n/4 - 3 =4n/4 - 3 =4?