How do you solve rational equations $\frac{5}{3 x - 4} = \frac{3}{x - 3}$ $5/(3x-4)=3/(x-3)$ ?

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How do you solve rational equations $\frac{5}{3 x - 4} = \frac{3}{x - 3}$ $5/(3x-4)=3/(x-3)$ ?

1 Answer

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Answer 1 · 2016-02-15T16:51:39

$x = - \frac{3}{4}$ $x= -3/4$

Explanation:

just simply cross multiply the equation $5 (x - 3)$ $5(x-3)$
$3 (3 x - 4)$ $3(3x-4)$ after solving this $5 x - 15 = 9 x - 12$ $5x-15=9x-12$
$5 x - 9 x = - 12 + 15$ $5x-9x=-12+15$
$- 4 x = 3$ $-4x=3$
$x = - \frac{3}{4}$ $x=-3/4$

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How do you solve rational equations $\frac{5}{3 x - 4} = \frac{3}{x - 3}$ $5/(3x-4)=3/(x-3)$ ?

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Explanation:

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How do you solve rational equations 5/(3x-4)=3/(x-3)53x−4=3x−35/(3x-4)=3/(x-3)?

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How do you solve rational equations $\frac{5}{3 x - 4} = \frac{3}{x - 3}$ $5/(3x-4)=3/(x-3)$ ?